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What is the polar form of -9-9i√3?

2 Answers

7 votes

Answer:

D

Explanation:

Ed2021

User NoBugs
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12 votes

Answer:

18(cos(4pi/3) + i sin(4pi/3))

Explanation:

step 1: find the modulus (|z|=√(a^2 + b^2)

|z|=√((-9)^2+(-9√3)^2)= 81+243= 324 => √324=18

step 2: find the argument using theta =tan^-1 (y/x)

theta=tan^-1((-9√3)/-9) = √3

the tangent value of √3 in the third quadrant has the degree measure of 240 and the radian measure of 4pi/3.

Now put them together!

User Vell
by
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