Question

On the surface of the moon, the value of g is 1.67 m/s2. What is the horizontal distance traveled during a 2.00-meter high jump if the jumper runs as at 20 miles per hour?

Answer 1

To solve this question, you need to find how long jump is. For 2m high with 1.67 m/s2 it would be:

h= 1/2 gt^2
2= 1/2 * (1.67) t^2
t^2= 1.67
t= 1.29

If the speed is 20 mph and the jump is 2 second, the distance traveled would be:
20 miles/ hour * 1.29 second * (1 hour/3600second)= 0.007179 miles

If you need to convert it to meter then: 0.007179 mile * 1609.34meter/ mile= 11.55 meter