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How do you do x ^4-4? What is the x values?

User Sverrisson
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we know that
A difference of two perfect squares (A² - B²) can be factored into (A+B) • (A-B)
then
x ^4-4--------> (x²-2)*(x²+2)
(x²-2)--------> (x-√2)*(x+√2)
x1=+√2
x2=-√2

the other term
(x²+2)=0-> x²=-2-------------- x=(+-)√-2

i is called the imaginary unit. It satisfies i² =-1
Both i and -i are the square roots of -1
-2 =√ -1• 2 = √ -1 •√ 2 =i • 2
The equation has no real solutions. It has 2 imaginary, or complex solutions.
x3= 0 + √2 i
x4= 0 - √2 i

the answer is

the values of x are
x1=+√2
x2=-√2
x3= 0 + √2 i
x4= 0 - √2 i

User Netcat
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