Question

What is the momentum of the system after the collision?

0.0 kg • m/s
0.2 kg • m/s
0.3 kg • m/s
0.4 kg • m/s

Answer 1

0.2

Step-by-step explanation:

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Answer 2

Answer: The momentum of the system after the collision is 0.2 kg m/s.

Step-by-step explanation:

According to the conservation of momentum, the total momentum of the system before the collision is same the total momentum of the system after the collision in an isolated system.

`m_(1)u_(1)+m_(2)u_(2)=m_(1)v_(1)+m_(2)v_(2)`

Here, m_{1},m_{2} are the first and second object, v_{1},v_{2} are the initial velocities of the first and second objects and u_{1},u_{2} are the final velocities of the first and the second objects.

Use the formula of the conservation of the momentum.

`m_(1)u_(1)+m_(2)u_(2)=m_(1)v_(1)+m_(2)v_(2)`

Put m_{1}=0.6 kg, m_{2}=0.5 kg, v_{1}=0.5 m/s and v_{2}=-0.2 m/s.

`m_(1)u_(1)+m_(2)u_(2)=(0.6)(0.5)+(0.5)(-0.2)`

`[tex]m_(1)u_(1)+m_(2)u_(2)`= 0.2 kg m/s[/tex]

Therefore, the momentum of the system after the collision is 0.2 kg m/s.