Question

The solution set for 7q2 − 28 = 0 is { }. (Separate the solutions with a comma) NextReset

Answer 1

7q^2 - 28 = 0

7q^2 = 28
q^2 = 4
q = +/-2
solution set is {-2,2}

Answer 2

{ 2,-2}

Explanation:

In order to solve this set we just have to first clear the "q":

`7q^(2) -28=0\\7q^(2) -28+28=+28\\7q^(2) =28\\(7q^(2))/(7)  =(28)/(7) \\q^(2)=4\\\sqrt{q^(2)} =√(4) \\q= 2, -2`

So as we know the solution for a square root is always a negative and positive number, so the solutions ser for 7q2-28=0 is 2 and -2