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A nuclide of 64/29 Cu absorbs a position. Which is the resulting atom?

A) 65/29 Cu
B) 63/29 Cu
C) 64/28 Ni
D) 64/30 Zn

User Jyao
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2 Answers

4 votes

Final answer:

When a nuclide of 64/29 Cu absorbs a positron, it undergoes a process called positron emission and the resulting atom is 63/29 Cu.

Step-by-step explanation:

When a nuclide of 64/29 Cu absorbs a positron, it undergoes a process called positron emission. During this process, one of the protons in the nucleus is transformed into a neutron, resulting in a new atom. The resulting atom will have the same number of protons as the original atom, but one less proton. Therefore, the resulting atom will be 63/29 Cu, which is option B.

User Ram Talreja
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6.1k points
4 votes
64Cu29 + 1e0 === > 65Cu29
User Haresh Vidja
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6.2k points