Question

An engine performs 2700 J of work on a scooter. The scooter and rider have a combined mass of 150 kg. If the scooter started at rest, what is the speed of the bike after the work is performed?

Answer 1

the person above me is right

Answer 2

Due to the principle of conservation of energy, the work done by the engine to move the scooter converts into kinetic energy of the scooter:

`W=K= (1)/(2) M v^2`
where M is the combined mass of scooter and rider, and v is the velocity of the scooter. Therefore, we can find the velocity as:

`v= \sqrt{ (2W)/(M) } = \sqrt{ (2\cdot 2700 J)/(150 Kg) }=6 m/s`