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TanA+tanB=sin(A+B)/cosAcosB
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TanA+tanB=sin(A+B)/cosAcosB
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Jul 11, 2019
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TanA+tanB=sin(A+B)/cosAcosB
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DorianFM
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Do you need to prove that it is equal?
If so:
SinA/cosA + sinB/cosB = (sinAcosB + sinBcosA)/cosAcosB
(SinAcosB + sinBcosA)/cosAcosB = (SinAcosB + sinBcosA)/cosAcosB
Ganesh M
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Jul 16, 2019
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Ganesh M
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