Question

A company sells cereal in two different -sized boxes.The smaller box has the dimensions of 12-inch,2-inch and 7 3/4 i.The height of the smaller box is 80% of the height of the lager box,while the other two dimensions are the same for both boxes.What is the difference in the volumes of the two boxes?

Answer 1

Answer: The answer is 232.5

Step-by-step explanation:First you to set up the proportion. If 80% equals to 12. You Would do 80 over hundred becuase percent is out of hundred (80/100) then you would do 12 over x or any other variable. FROM there on you would to the butter fly method. Cross multiply . ( 80 times variable, 12 times 100) now to isolate the variable you have to do inverse operation. So now do 1200 divided by 80 . And 80 divided by 80. Now you know.

X=15.

But were no done yet lol. Now do length times width times height to get the volume. 15 times 2 times 31/4 (7 3/4) . now we're done. Your welcome

Answer 2

We will take the volume of each box separately to find the difference between them.
We have then that the volume of the boxes is:
V = (L) * (W) * (h)
Where,
L: long
W: width
h: height
The smaller box:
V1 = (12) * (2) * (7 3/4)
V1 = 186 in ^ 3
the lager box:
V2 = (12) * (2) * ((7 3/4) * (100/80))
V2 = 232.5 in ^ 3
The difference is:
V2-V1 = 232.5 in ^ 3 - 186 in ^ 3 = 46.5 in ^ 3
Answer:
The difference in the volumes of the two boxes is:
46.5 in ^ 3