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Write an equation in standard form of the line passing through points

Write an equation in standard form of the line passing through points-example-1
User Rahul Ravi
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\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ -(4)/(9) &,& (4)/(9)~) % (c,d) &&(~ (6)/(5) &,& (4)/(5)~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{(4)/(5)-(4)/(9)}{(6)/(5)-\left( -(4)/(9) \right)}\implies \cfrac{(4)/(5)-(4)/(9)}{(6)/(5)+(4)/(9)}


\bf \cfrac{\quad (36-20)/(45)\quad }{(54+20)/(45)}\implies \cfrac{\quad(16)/(45) \quad }{(74)/(45)}\implies \cfrac{16}{45}\cdot \cfrac{45}{74}\implies \cfrac{16}{74}\implies \cfrac{8}{37} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-\cfrac{4}{9}=\cfrac{8}{37}\left[ x -\left( -\cfrac{4}{9} \right)\right]


\bf y-\cfrac{4}{9}=\cfrac{8}{37}\left( x +\cfrac{4}{9} \right)\implies y-\cfrac{4}{9}=\cfrac{8}{37}x+\cfrac{32}{333} \\\\\\ y=\cfrac{8}{37}x+\cfrac{32}{333}+\cfrac{4}{9}\implies y=\cfrac{8}{37}x+\cfrac{32}{333}+\cfrac{148}{333}\implies y=\cfrac{8}{37}x+\cfrac{180}{333} \\\\\\ y=\cfrac{8}{37}x+\cfrac{20}{37}\implies \stackrel{standard~form}{-\cfrac{8}{37}x+y=\cfrac{20}{37}}
User Weishi Z
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