Question

PLEASE SOLVE FOR ME!!!! I am stuck on question...

36/5x - 10 < 5

Answer 1

`*\ (36)/(5x) - 10 \ \textless \ 5 \qquad x \\eq 0 \\ \\ \\ (36)/(5x)\ \textless \ 5 + 10 \\ \\ \\ (36)/(5x)\ \textless \ 15 \\ \\ \\ 36\ \textless \ 15 * (5x) \\ \\ 36 \ \textless \ 75x \\ \\ (36)/(75)\ \textless \ x \qquad (12)/(25)\ \textless \ x \qquad \boxed{x\in ( (12)/(25); +\infty) }`




`*\ (36)/(5x-10) \ \textless \ 5 \qquad x \\eq 2 \\ \\ \\36 \textless \ 5 (5x-10) \\ \\ 36 \textless \ 25x-50 \\ \\ 36+50\ \textless \25x \\ \\ 86 \ \textless \ 25x \\ \\ (86)/(25)\ \textless \ x\qquad \to \qquad \boxed{x\in ( (86)/(25); +\infty) }`