Question

Evaluate log49 base 1/7​

Answer 1

- 2

Explanation:

using the rule of logarithms

`log_(b)` x = n ⇒ x =
`b^(n)`

given

`log_{(1)/(7) }` 49 = n , then

49 =
`((1)/(7)) ^(n)`

49 =
`(7^-1)^(n)` , that is

7² =
`7^(-n)`

since bases on both sides are equal then equate exponents

- n = 2 ( multiply both sides by - 1 )

n = - 2

Answer 2

Explanation:

Exact Form:

1/2

Decimal Form:

-0.5