Question

Solve. x² + 20x + 100 = 50

A)x=−10±52√
​B)x=50±252√ ​
​C) x=10±52√ ​ ​
​D)x=50±52√ ​

Answer 1

x² + 20x + 100 = 50
x = −10 ± 5√2

Answer 2

Solve. x²+ 20x + 100 = 50

Subtracting 50 from both sides

`x^(2) +20x+100-50=50-50`

`x^(2) +20x+50=0`

To solve the quadratic equation, let us use quadratic formula

For,
`ax^(2) +bx+c=0` ,
`x=\frac{-b+-\sqrt{b^(2)-4ac}}{2a}`

So, a=1, b=20, c=50

So, we get,

x=
`\frac{-20+-\sqrt{20^(2)-4*1*50}}{2*1}`

`x=(-20+-√(400-200))/(2)`

`x=(-20+-√(200))/(2)`

`x=(-20+-10√(2))/(2)`

`x=(-10+-5√(2))/(1)`

`x=-10+-5√(2)`

Option(a) Answer

So, x=-10+5
`√(2)`

or, x=-10-5
`√(2)`