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Three consecutive multiples of 3 have a sum of 36.
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Three consecutive multiples of 3 have a sum of 36.

User Suliman Farzat
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1 Answer

4 votes
Charstar Ambitious36= x+y+z
In terms of x:
x=x
y=x+3
z=x+6

36= x+x+3+x+6
36=3x+9
27=3x
x=9
9+6=15
The largest is 15
User Mathieu Westphal
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