Question

Which equation is in the point slope-form and is depicted by this graph

Answer 1

Step-by-step explanation

iven the points (-1,-4) and t(3,2). The points slope form of the equation can be found using the formula

`\begin{gathered} y-y_1=m(x-x_1) \\ y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1) \\ where\text{ x}_1,y_1=-1,-4 \\ x_2,y_2=3,2 \end{gathered}`

We would then substitute the value into the formula;

`\begin{gathered} y-(-4)=(2-(-4))/(3-(-1))(x-(-1)) \\ y+4=(6)/(4)(x+1) \\ y+4=(3)/(2)(x+1) \end{gathered}`

Answer: Option 3