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How do you solve 10x + 7 = 2(5x - 8) and 3(3b + 1) = 2(7b - 21)?
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How do you solve
10x + 7 = 2(5x - 8) and
3(3b + 1) = 2(7b - 21)?

User Arthur Ulfeldt
by
6.9k points

1 Answer

6 votes
10x+7=2(5x-8)
10x+7=10x-16
+16 +16
10x+23=10x
-10x -10x
23=0

3(3b+1)=2(7b-21)
9b+3=14b-42
+42 +42
9b+45=14b
-9b -9b
45=5b
9=b
User Chornbe
by
8.0k points
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