144k views
2 votes
If a right triangle has a leg that measures 24 and a hypotenuse that measures 25. what is the length of the other leg?

2 Answers

2 votes
hypotenuse ^2= leg1 ^2+ leg2 ^2

25^2= 24^2 + leg2 ^2

leg2 ^2= 25^2-24^2= 625- 576=49

⇒ leg = V49
leg= 7
User Ynka
by
7.4k points
4 votes
Phytagoras' Theorem states that in any right triangle, the square of the hypotenuse is equal to the sum of the squares of the two legs. If c represents the hypotenuse, a and b represent the two leg, the theorem could be written as below.
c² = a² + b²
a² + b² = c

From the question, we could get information that
c = 25
a = 24
and we should find the value of b

Plug in the numbers to the formula
a² + b² = c²
24² + b² = 25²
576 + b² = 625
b² = 625 - 576
b² = 49
b = √49
b = 7

The length of the other leg is 7
User ChrisJJ
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories