222k views
5 votes
Given the geometric sequence where a1 = 2 and r = √2 find a9

32
32√2
256
256√2

2 Answers

2 votes
a9=a1*r^8

a9= 2*V2^8=2*2^4=2^5

a9 = 32
User Ajay Jadhav
by
8.8k points
2 votes

Answer: First option is correct.

Explanation:

Since we have given that

There is a geometric sequence:

where a₁ = 2

r = √2

We need to find a₉:

As we know the formula for "nth term ":


a_n=ar^(n-1)\\\\a_9=ar^(9-1)\\\\a_9=ar^8\\\\a_9=2* (√(2))^8\\\\a_9=32

Hence, First option is correct.

User Tanishka Gupta
by
8.6k points