Step-by-step explanation
From the statement, we know that:
0. the company sells 1000 packs of cards per day for $5 per pack,
,
1. with every $0.02 reduction in price, 10 more packs a day are sold.
To solve this problem, we define the following variables and functions:
• r = # of price reductions,
• n(r) = # of packs sold by the company as a function of r,
,
• p(r) = price per pack (in $) as a function of the # of price reductions,
,
• I(r) = income (in $) as a function of the # of price reductions.
Using points 1 and 2, we write the following functions: function of # of packs sold n(r) as:
• the i
• the function of the price per pack p(r):
• the function for the income I(r) is given by the product of the # of packs sold n(r) and the price per pack p(r):
(1) To find the maximum income, we must maximize the function I(r) for r. To do that, we compute and make equal to zero its first derivative:
Solving for r, we get:
We have found that the maximum income is achieved when the # of price reductions is equal to r = 75.
(2) s
We have found that the maximum possible income per day is $6125.
(3) s
We have found that the price per pack that maximizes the income is $3.5.
(4) s
With this new price structure, the company wins $6125 s
Answer
• The maximum possible income per day is $6125.
,
• The price per pack that maximizes the income is $3.5.
,
• The company makes $1125 extra with this new price structure.