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For f(x)=4x+1 and g(x)=x^2-5 find (fog)(x)

2 Answers

5 votes
(fog)(x)= f(g(x))= 4(x^2-5)+1= (4•x^2)-20+1=

(4•x^2)-19
User Kmatyaszek
by
8.1k points
2 votes

Answer:

(fog)(x) =
4x^(2)-19

Explanation:

The given functions are f(x) = 4x + 1 and g(x) =
x^(2)-5

We have to find the value of (fog)(x).

Since (fog)(x) = f[g(x)]

It means we have to find the value of f(x) for the value of x = g(x)

Now f[g(x)] =
4[x^(2)-5]+1

=
4x^(2)-20+1

=
4x^(2)-19

Therefore, f[g(x)] =
4x^(2)-19 will be the answer.

User Mathias Dewelde
by
8.5k points

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