Question

PLEASE FULL ANSWERS! need all the help I can get

Answer 1

a. f(-1) = (1-1)/(-1+1) = 0
This is still continuous I believe as the whole y equals 0, though I am not sure about this.

b. f(1) = (1-1)/(1+1)= 0
This is definitely continuous as the denominator did not equal 0.

Answer 2

A
This is one of those questions that is hard to explain, because I don't know what you know. I'll start with the most obvious reason I know. At x = -1 the top and bottom of the function is 0/0. zero/zero can give indeterminate results and you must look for other ways of explaining what is going on. Here's another thought which is less reliable.

The fraction factors.
(x + 1)*(x - 1)
============
(x + 1)
The two common factors cancel and you are left with f(x) = x - 1

If you have a graphing calculation you can put this in as y = x - 1 and you see that it is a straight line.

Question B is much nicer
when you put x = 1 into the fraction, you get 0 /2 which gives you 0. That's much easier to handle because the answer is 0.
you are still graphing y = x - 1, but this time the graph is much more well behaved.