Question

The equation of the graphed line in point-slope form is what

Y-0=-3/5(x-3)

3y=-5(x-3)

Y-3=-3/5(x-0)

And it’s equation in slope-intercept form is what

Y=-9/5x+3/5

5y=-3(x-3)

Y=-3/5x+9/5

Answer 1

(-2,3) (3,0)

find slope
m= 0-3/(3+2) = -3/5

point slope is y-y1=m (x-x1)

point is (3,0) and m=-3/5

plug and chug

y-0=-3/5(x-3)

y=-3/5x+9/5

hope that helps