Question

How many grams are in 869 moles of FeCL2?

Answer 1

there are 110,141.405 grams of FeCl2

Answer 2

The first step we have to follow is to find the molar mass of FeCl2 using the atomic masses of each element:

`\begin{gathered} Fe=55.845g/mol \\ Cl=35.45g/mol*2=70.9g/mol \\ FeCl_2=126.745g/mol \end{gathered}`

It means that each mole of FeCl2 has a mass of 126.745g/mol.

Use the molar mass to find the mass of the given amount of moles:

`869molFeCl_2\cdot(126.745gFeCl_2)/(1molFeCl_2)=110,141.405gFeCl_2`

It means that there are 110,141.405 grams of FeCl2.

In scientific notation it would be 1.10x10^5g.