Question

The molarity of a solution that contains 14 g KOH per 150 mL of solution is:

Answer 1

The molarity of a solution that contains 14 g KOH per 150 mL of solution is 1.7 m

Answer 2

1.67 M

Step-by-step explanation:

Molarity =
`(moles)/(liter)`

Moles =
`(mass)/(molar mass)`

Given

Mass of KOH = 14 g

Molar mass of KOH = 56.1056 g/mol

Moles of KOH =
`(14 g)/(56.1056 g/mol)` = 0.25 mol

Volume of solution = 150 ml = 0.15 L (1 L = 1000 ml)

Molarity =
`(0.25 mol)/(0.15 L )`= 1.67 M