Question

What is the equation of a line perpendicular to 2x-3y=6 and passes through the point (6,-1) ?

Answer 1

y=-3/2x+8

Explanation:

Alright so first we need to convert this equation to Y=mx+b form.

We get y=2/3x-2

In order for it to be perpendicular, we must use -3/2 as the slope.

y=-3/2x+b

Next we need to find the y-intercept of this

Plug in 6 for x and -1 for y and solve for b

b=8

Hope this helps :-)