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What are the real zeros y=(x+3)^3+10?
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What are the real zeros y=(x+3)^3+10?

User Dprevite
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1 Answer

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There is only 1
(x + 3)^3 + 10 = 0
(x + 3)^3 = - 10
(x + 3) = cuberoot(-10)
x = -3 + cuberoot(-10)
User Sisanared
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