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Sin(a+b)/sin(a-b)=tana+tanb/tana-tanb a= alpha b = beta I can get to this from the left side, sinacosb+cosasinb/sinacosb-cosasinb, not sure how to prove it from there.
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Sin(a+b)/sin(a-b)=tana+tanb/tana-tanb

a= alpha b = beta

I can get to this from the left side,

sinacosb+cosasinb/sinacosb-cosasinb, not sure how to prove it from there.

User Desaray
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2 Answers

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(sinacosb+cosasinb)/sinacosb-cosasinb then you divide both the numerator and denominator by cosacosb, it will give you the right side
User Sangram Nandkhile
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8.9k points
7 votes
you should divide the top # and the bottom # by cosacosb
User Pfernandom
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