Question

In a certain species of plant, flowers occur in three colors: blue, pink, and white. a pure-breeding pink plant is mated with a pure-breeding white plant. all of the f1 are blue. when the blue f1 plants are self-fertilized, the f2 occur in the ratio 9 blue:3 pink:4 white. (c) what is the genotype of the f1 plants? use b/b for the hypostatic gene and w/w for the epistatic gene.

Answer 1

The genotype of the blue F1 plants in the described dihybrid cross with epistasis is BbWw, where Bb is for the hypostatic gene for blue color and Ww is for the epistatic gene that suppresses the blue color expression.

Step-by-step explanation:

The question is asking for the genotype of the F1 plants when a pure-breeding pink plant is mated with a pure-breeding white plant, resulting in all blue F1 plants. With a given F2 ratio of 9 blue:3 pink:4 white, this suggests a dihybrid cross with epistasis, where one gene affects the expression of another.

Since B is associated with the blue color and is hypostatic (recessive epistasis) while W is the epistatic gene, the parental plants must have genotypes of bb (blue) and ww (white/pink). For the blue F1 progeny to occur, they need to inherit a b from each parent (hence, they are Bb) and at least one dominant W allele to suppress the expression of the recessive b allele. Therefore, the genotype of the blue F1 plants would be BbWw.

Answer 2

I wish I could help sorry