Question

A person used a lever to lift a machine with 200 newtons of resistance force 0.2 meters. The person applied 150 newtons of effort force and pushed the end of the lever 0.5 meter.

A. What is the work output?____________
B. What is the work output?____________
C. What is the efficency of the lever?_________

Answer 1

work = force * distance

work output = 200N * 0.2m = 40J
work input = 150N * 0.5m = 75J
efficency = output/input = 40/75 = 0.53 = 53%