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I need help solving this problem.
4x cos ^(-1) (2x+4)- \sqrt{3-3 x^(2) }, find f'(x). My original which is wrong, is included.

I need help solving this problem. 4x cos ^(-1) (2x+4)- \sqrt{3-3 x^(2) }, find f'(x-example-1
User Ipave
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2 Answers

3 votes
Given:

f(x)=4xcos^(-1)(2x+4)-√(3-3x^2)

Using

(d)/(dx)cos^(-1)(x)=-(1)/(√(1-x^2))
we derive

(d)/(dx)4xcos^(-1)(2x+4)

=4cos^(-1)(2x+4)-(8x)/(√(1-(2x+4)^2))

Similarly, using

(d)/(dx)√(x)=(1)/(2√(x))
we derive

(d)/(dx)(-√(3-3x^2))

=(3x)/(√(3-3x^2))

Therefore, the derivative is

f'(x)=(d)/(dx)(4xcos^(-1)(2x+4)-√(3-3x^2))

=4cos^(-1)(2x+4)-(8x)/(√(1-(2x+4)^2))+(3x)/(√(3-3x^2))
User Jocelynn
by
8.9k points
5 votes
I believe it's as follows:


f'(x) = 4(acos(2x+4)- (2x)/( √(-4x^2-16x-15)))+ (3x)/( √(3-3x^2))
User Darmen Amanbay
by
8.0k points

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