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How to solve thus through substitution method. please do it step by step

How to solve thus through substitution method. please do it step by step-example-1
User Chillin
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4x-6y=9
2x+3y=4

4x=9+6y
X=9/4+6y/4
2(9/4+6y/4)+3y=4
18/4+12y/4+3y=4
9/2+6y=4
6y=8/2- 9/2
6y= -1/2
y= -1/12 x= 17/8
User Tmullaney
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4 votes
Hey there!

To start, first solve the equation of -2x + 3y =4 for the value of x since the coefficients appear to be smaller and easier to work with than the equation 4x- 6y= 9.

To solve -2x+3y=4 for x, first subtract both sides by 3y to isolate -2x:
-2x+3y=4
-2x=-3y+4

Now, divide both sides by -2 to isolate or solve for the x variable:
-2x=-3y+4
x=3/2y-2

Now that you have x set equal to the expression 3/2y-2, substitute this value for x in the equation 4x-6y=9:
x=3/2y-2
4x-6y=9
4(3/2y-2)-6y=9

Now, simplify this expression and combine your like terms:
4(3/2y-2)-6y=9
(4*3/2y)+(4*-2)-6y=9
6y-8-6y=9
-8=9

Because you end up in an untrue mathematical statement, your answer would be that there are no real solutions for this system.

Hope this helps and have a marvelous day! :)



User Jonathan DeMarks
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