Answer:
Rate when he drove to visit his parents = 55 miles per hour
Rate when he was coming home = 55 + 11 = 66 per hour
Explanation:
The journey can be categorized into two phase:
when Justin was visiting his parents and when he was returning home.
let's compute the values of when he was returning home.
distance = 240 miles
let the rate = y
rate = distance/time
time = distance/rate
time = 240/y
let's compute the values of when he drove to visit his parents
distance = 240 miles
According to the question the rate was 11 miles per hour faster than on his way home. it can be represented as
rate = y + 11
rate = distance/time
time = distance/rate
time = 240/y + 11
The total time spent travelling is 8 hrs therefore,
240/y + 240/(y + 11) = 8
multiply through by y (y + 11)
240/y × y(y + 11) + 240/(y + 11) × y(y + 11) = 8 × y × (y + 11)
240 (y + 11) + 240 y = 8y(y + 11)
240y + 2640 + 240y = 8y² + 88y
480y - 88y - 8y² + 2640 = 0
392y - 8y² + 2640 = 0
8y² - 392y - 2640 = 0
divide through by 8
y² - 49 - 330 = 0
(y - 55) (y + 6) = 0
Therefore y = 55 . Note y cannot be -6.
Rate when he drove to visit his parents = 55 miles per hour
Rate when he was coming home = 55 + 11 = 66 per hour