Question

A projectile is fired vertically from earth's surface with an initial speed of 5.3 km/s. neglecting air drag, how far above the surface of earth will it go?

Answer 1

The projectile will reach a maximum height of 145.51 km above the surface of the Earth when neglecting air drag.

Step-by-step explanation:

To find the maximum height reached by the projectile, we need to use the equations of motion for projectile motion. When a projectile is fired vertically upwards, its final velocity at the highest point is 0 m/s. Using the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (-9.8 m/s^2), and s is the displacement, we can solve for s:

0 = (5.3 km/s)^2 + 2*(-9.8 m/s^2)*s

s = (5.3 km/s)^2 / (2*(-9.8 m/s^2))

s = 145.51 km

Therefore, the projectile will reach a maximum height of 145.51 km above the surface of the Earth when neglecting air drag.

Answer 2

It will rise, and then fall back to the Earth’s surface.