Question

(-3,-4); y=-2x+5 equation for the line in slope-intercept form

Answer 1

Parallel lines have the same slope
`m` and never coincide. So to write a line that passes through the given point and has slope -2, it is helpful to write this into point-slope form,
`y-y_1 = m(x-x_1)`. We use the given point, (-3, -4). Substituting this in, we get
`y - (-4) = -2(x-(-3))`, or
`y + 4 = -2(x+3)`. Now, you should distribute the -2 and subtract four from both sides to get this into slope-intercept form,
`y = mx+b`. Doing that, you get
`y = -2x -10`.

You can verify that it indeed satisfies the requirements because (-3, -4) is a solution of the equation.
`-4 = -2(-3) -10 = -4`