Question

A 10.0-kilogram block rests motionless on a horizontal, frictionless table. How

much work must be done to accelerate the block to a speed of
5.00 meters per second?

Answer 1

Answer:125 J

Step-by-step explanation:

Given

Mass of block
`m=10\ kg`

Initial velocity
`u=0\ m/s`

Final velocity
`v=5\ m/s`

According to the work-energy theorem, work done by all the forces is equal to the change in kinetic energy.

As the block is on the horizontal surface so, the work done by gravity is zero.

Work(W)=change in kinetic Energy

`W=(1)/(2)m[v^2-u^2]\\W=(1)/(2)* 10* [5^2-0^2]=125\ J`