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A man stands still on a moving walkway that is going at a speed of 0.3 m/s to the south. What is the velocity of the man according to a stationary observer?

User Sudhakar B
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2 Answers

4 votes
The velocity is 0.3 m/s South.
User Tbc
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6 votes

Answer:

With respect to stationary observer the velocity of man is 0.3 m/s towards South

Step-by-step explanation:

As we know that here man is standing still on the moving walkway

so here we can say that velocity of man with respect to walkway is zero


\vec v_(mw) = 0

now as per relative velocity concept we know


\vec v_(mw) = \vec v_m - \vec v_w

here we know


\vec v_m = velocity of man with respect to stationary observer


\vec v_w = velocity of walkway

now from above equation we have


\vec v_m = \vec v_(mw) + \vec v_w

now plug in all values in it


\vec v_m = 0 + 0.3 m/s = 0.3 m/s towards South

User Saatana
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