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For f(x) =2x+1 and g(x)=x^2-7, fine (f*g)(x)
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For f(x) =2x+1 and g(x)=x^2-7, fine (f*g)(x)

User Khristian
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1 Answer

6 votes
(f * g)(x)

(2x + 1)(x^2 - 7) =
2x(x^2 - 7) + 1(x^2 - 7) =
2x^3 - 14x + x^2 - 7 =
2x^3 + x^2 - 14x - 7 <===
User Ariel Weinberger
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