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These triangles are similar so how do I solve for x?
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3 votes
These triangles are similar so how do I solve for x?

These triangles are similar so how do I solve for x?-example-1
User Ameeta
by
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1 Answer

3 votes
2x - 11/21 = 12/28

21 ° 12 = 28(2x - 11)

252 = 56x - 308

252 + 308 = 56x

560 = 56x

560/56 = x

10 = x

User Ponleu
by
8.0k points
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