Answer:
A. 2.2% is correct.
Explanation:
Deposit Amount = $60
Pearl saving $60 into an account with interest is compounded monthly.
Her money is double in approximately 33 years.
Formula

where,
A is final amount. (Double of initial value). A=$120
P is deposit amount. P=$60
r is rate of interest. r=?
n number of period. n=12
t is total time. t=33
Substitute all these values into formula.

Now we solve for r

Taking log both sides





Thus, Rate of interest is 2.2%