62.1k views
4 votes
At the end of each day, helen throws all the change from her purse into a box. the box contains only pennies, nickels, and dimes. at the end of one week she found that the total value of the coins was $6.43. if the number of dimes was 3 more than the number of nickels and the number of pennies was 5 more than the number of nickels, how many dimes were in the box?

1 Answer

0 votes
If you subtract the value of the extra dimes and pennies, you have groups of coins consisting of 1 dime, 1 nickel, and 1 penny, worth 16¢. The value of this reduced collection is $6.43 -0.35 = $6.08. That is the value of
.. 6.08/.16 = 38 . . . . groups of coins.

There were 38 +3 = 41 dimes in the box.
User Ahoff
by
7.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories