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If f(x)=x^2+1 and g(x)=x-4, which value is equivalent to (f o g)(10)?

User Simran
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2 Answers

7 votes
f(g(x)) = g(x)^2 + 1
f(g(x)) = (x - 4)^2 + 1
f(g(x)) = (10 - 4)^2 + 1
f(g(x)) = 36 + 1
f(g(x)) = 37

User Sarosh
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8.2k points
2 votes
This is equivalent to
f(g(x)) = x^2 + 1 That means wherever you see an x on the right, you put in g(x)

f(g(x)) = g(x)^2 + 1
f(g(x)) = (x - 4)^2 + 1 Now you can put in the 10
f(g(x)) = (10 - 4)^2 + 1
f(g(x)) = 36 + 1
f(g(x)) = 37
User Mpersico
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8.6k points