Question

What is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (–5, 1)? Check all that apply. y = −x − 1 2x + 5y = −5 y = −x − 3 2x + 5y = −15 y − 1= −(x + 5)

Answer 1

its the first second and last one its kinda annoying i got the question wrong because I listened to this guy

Answer 2

Option B. 2x + 5y = -5

Explanation:

We have to get the equation of a line which is parallel to the line 2x + 5y = 10

and passes through the point (-5, 1).

Since the line is parallel to 2x + 5y = 10 then slope of this line will be equal to the new line.

5y = -2x + 10

y = (-2x/5) + (10/5)

y = -2x/5 + 2

Therefore slope m = -2/5

So the equation of parallel line will be

y = (-2/5) x + c

Here c is the y- intercept.

Now this line passes through ( -5, 1)

So 1 = 2×5/5 + c

c = 1 - 2 = -1

So the equation will be

y = (-2/5)x - 1

5y = -2x - 5

2x + 5y = -5

Therefore Option B. 2x + 5y = -5 is the answer.