Question

A 70 kilogram mountaineer is standing on the summit of Mt. Everest. The distance between the mountaineer and the center of Earth is 6.39 × 106 meters. What is the magnitude of the force of gravity acting on the mountaineer? (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)

Answer 1

F = GMm/r²
F = (6.673*10^-11)(5.98*10^24)(70)/(6.39*10^...
F = 684 N (3sf)

Answer 2

Answer: The magnitude of the force of gravity acting on the mountaineer 684.09 Newtons.

Step-by-step explanation:

Mass of the earth , M =
`5.98* 10^{24] kg`

Mass of the mountaineer, m = 70 kg

Distance between mountaineer and Earth,r :
`6.39* 10^(6) m`

Gravitational constant ,G =
`6.673* 10^(-11) N m^2/kg^2`

`F=G(Mm)/(r^2)=6.673* 10^(-11) N m^2/kg^2(5.98* 10^(24) kg* 70 kg)/((6.39* 10^(6) m)^2)`

`F=684.09 N`

The magnitude of the force of gravity acting on the mountaineer 684.09 Newtons.