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A 0.580-kg rock is tied to the end of a string and is swung in a circle with a radius of 0.500 meters. The velocity of the rock is 4.50 m/s. What is the centripetal force acting on the rock
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A 0.580-kg rock is tied to the end of a string and is swung in a circle with a radius of 0.500 meters. The velocity of the rock is 4.50 m/s. What is the centripetal force acting on the rock

User Alexander Subbotin
by
8.0k points

2 Answers

3 votes

Answer:

23.5 Newtons

Have a ni day

User C Walker
by
8.6k points
2 votes

F = m (v^2)/(r)


F= 0.58 (4.5^2)/(0.5) = 23.49 N

User Insilico
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8.0k points
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