Question

What is the mass percentage of iodine (i2) in a solution containing 4.0×10−2 mol i2 in 140 g of ccl4?

Answer 1

(0.058 mol I2)(253.808 g/mol I2) = 14.721 g of I2
So that's the mass of I2: 14.721 g
Percentage is the mass of solute/(mass of solute + mass of solvent)

14.721/(14.721g + 105 g)
14.721/119.721
=0.123 or 12.3%

Answer 2

Answer: The mass percent of iodine in the solution is 6.77 %

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

We are given:

Moles of iodine gas =
`4.0* 10^(-2)=0.04moles`

Molar mass of iodine gas = 254 g/mol

Putting values in above equation, we get:

`0.04mol=\frac{\text{Mass of iodine gas}}{254g/mol}\\\\\text{Mass of iodine gas}=(0.04mol* 254g/mol)=10.16g`

To calculate the percentage composition of a substance in a solution, we use the equation:

`\%\text{ composition of substance}=\frac{\text{Mass of substance}}{\text{Mass of solution}}* 100`

We are given:

Mass of solute (iodine gas) = 10.16 g

Mass of solvent (carbon tetrachloride) = 140 g

Mass of solution = (140 + 10.16) g = 150.16 g

Putting values in above equation, we get:

`\text{Mass percent of iodine in solution}=(10.16)/(150.16)* 100\\\\\text{Mass percent of iodine in solution}=6.77\%`

Hence, the mass percent of iodine in the solution is 6.77 %