The formula for margin of error is:

From this equation, we can eliminate n, which will be:

We have to find the number of subjects (n) for the second poll.
We have p = 0.6
q = 1 - p = 0.4
z = 1.645
E for second poll is unknown.
It is given that Margin of error of second poll is 3 times the margin of error of first poll. So if we find margin of error of first poll, we can use it to calculate margin of error of second poll.
Using the data for first poll to calculate E:

Margin of error for second poll will be = 3 x 0.049 = 0.147
Now using this value to calculate number of subjects in second poll:

Thus approximately 30 subjects were surveyed in the second poll.