Question

Suppose a lion running at a velocity of 10 m/s east slows

down. After 30 seconds, the lion has stopped. What is the
lion's acceleration?

Answer 1

`a=0.34\ m/s^2`

Step-by-step explanation:

Given that,

Initial velocity, u = 10 m/s

Final velocity, v = 0 (stops)

Time, t = 30 s

We need to find the acceleration of the lion.

We know that,

Acceleration = rate of change of velocity

`a=(v-u)/(t)\\\\a=(10-0)/(30)\\\\a=0.34\ m/s^2`

So, the acceleration of the lion is
`0.34\ m/s^2`.