Answer: 448 g of
will be required to completely react with 784g moles of CO(g) during this reaction.
Step-by-step explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
2 moles of
require = 1 mole of
Thus 28 moles of
will require=
of
Mass of
Thus 448g of
will be required to completely react with 784g moles of CO(g) during this reaction.