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If a sample of pure silver (Ag) contains 3.35 x 1022 atoms of silver, how many moles of silver are in the sample?

User Igor S
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hey there!:

1 mole Ag ------------------- 6.02*10²³ atoms
moles Ag ?? --------------- 3.35 *10²² atoms

moles Ag = ( 3.35*10²² ) * 1 / ( 6.02*10²³ ) =

moles Ag = ( 3.35*10²² ) / ( 6.02*10²³ ) =

=> 0.5564 moles of Ag

hope this helps!
User IDrwish
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Answer: The given number of silver atoms occupies 0.055 moles.

Step-by-step explanation:

We are given:

Number of silver atoms =
3.35* 10^(22)

According to mole concept:

1 mole of an element contains
6.022* 10^(23) number of atoms.

So, using this concept:

As,
6.022* 10^[23} number of atoms occupies 1 mole of a element.

So,
3.35* 10^(22) number of atoms will have occupy
(1mole)/(6.022* 10^(23))* 3.35* 10^(22)=0.055mole of silver element.

Thus, the given number of silver atoms occupies 0.055 moles.

User CFou
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