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Justin wants to evaluate 3cot(-5pi/4). Which of the following identities can he use to help him? Select two answers.

cot(-theta) = cot(theta)
cot(-theta) = -cot(theta)
cot(-theta) = cot(-theta)
cot(theta + pi) = cot(theta)
cot(theta + 2pi) = cot(theta)

User Trevorsky
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2 Answers

5 votes
I would be the second and fourth one. If this is the test from connexus that is 3 questions:Behavior of Trigonometric Functions Practice the answers are
1. d (4pi)
2. b,d as seen above
3. a,b (f(x)=csc x), (f(x)=1/sin x
User Petter Hesselberg
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7 votes

Answer:


\cot(-\theta)=-\cot(\theta)

and


\cot(\theta+\pi)=\cot(\theta)

Explanation:

Justin wants to evaluate


3\cot(-(5\pi)/(4)).

First he can use the fact that, the cotangent function is an odd function and write.


3\cot((5\pi)/(4))=-3\cot((5\pi)/(4)).

Also the cotangent function is positive in both the first and third quadrant, so we can use the symmetric property;


-3\cot(\pi+(\pi)/(4))=-3\cot((\pi)/(4)).

Hence the correct answers are;


\cot(-\theta)=-\cot(\theta)

and


\cot(\theta+\pi)=\cot(\theta)

User Pierre Chevallier
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