Answer:
![\cot(-\theta)=-\cot(\theta)](https://img.qammunity.org/2019/formulas/mathematics/high-school/aqrac96dybw36hgmvopl72gct4uu2ahh64.png)
and
![\cot(\theta+\pi)=\cot(\theta)](https://img.qammunity.org/2019/formulas/mathematics/high-school/aadli5ntmk7h263shvid652x7dwjehz25c.png)
Explanation:
Justin wants to evaluate
.
First he can use the fact that, the cotangent function is an odd function and write.
.
Also the cotangent function is positive in both the first and third quadrant, so we can use the symmetric property;
.
Hence the correct answers are;
![\cot(-\theta)=-\cot(\theta)](https://img.qammunity.org/2019/formulas/mathematics/high-school/aqrac96dybw36hgmvopl72gct4uu2ahh64.png)
and
![\cot(\theta+\pi)=\cot(\theta)](https://img.qammunity.org/2019/formulas/mathematics/high-school/aadli5ntmk7h263shvid652x7dwjehz25c.png)